The expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
Given an integral .
We are required to express the integral as a limit of Riemann sums.
An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.
A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.
Using Riemann sums, we have :
=∑f(a+iΔx)Δx ,here Δx=(b-a)/n
=f(x)=
⇒Δx=(5-1)/n=4/n
f(a+iΔx)=f(1+4i/n)
f(1+4i/n)=
∑f(a+iΔx)Δx=
∑
=4∑
Hence the expression of integral as a limit of Riemann sums of given integral is 4 ∑ from i=1 to i=n.
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4
2² simplified means 2 times 2 (2 times itself) so
2² = 4
2×2=4
2²=4
Now , it doesn't make any difference with a number like 2 .
Suppose we had 3 :
3² = 9
3² is not the same as 3 ×2 , and here's the reason for that :
3²=3×3=9
3 × 2 = 6
Answer:
i belive -2
Step-by-step explanation:
Answer:
see below
Step-by-step explanation:
Subtract 62, then divide by -32 to put the equation into intercept form:
... x/(-6.4) + y/(-10 2/3) = 1
This tells you the x-intercept is -6.4, and the y-intercept is -10 2/3. A line through these two points is your graph.