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OlgaM077 [116]
4 years ago
12

Why is it important that we tell Native American stories?

Mathematics
1 answer:
Orlov [11]4 years ago
6 0

Answer:

Utilizing storytelling to transmit educational messages is a traditional pedagogical method practiced by many American Indian tribes. American Indian stories are effective because they present essential ideas and values in a simple, entertaining form. Different story characters show positive and negative behaviors.

Step-by-step explanation:

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Find the ratio as simply as possible in the form a : b.
Charra [1.4K]
<h2>>> Answer </h2>

_________

\:

3 \frac{1}{2}  : 1 \frac{1}{7}

=  \frac{3 \frac{1}{2} }{1 \frac{1}{7} }

=  \frac{ \frac{7}{2} }{ \frac{8}{7} }

=  \frac{7}{2}  \times  \frac{7}{8}

=  \frac{49}{16}

= 49  : 16

7 0
3 years ago
A bracelet is originally $25 and it is now on sale. Sara paid $21.25 for the bracelet. What is the percentage of the discount? G
Alexxandr [17]

Answer:

  • 15%

Step-by-step explanation:

<u>Given</u>

  • Initial price = $25
  • Sale price = $21.25

<u>Discount </u>

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<u>Discount %</u>

  • 3.75/25*100% = 15%
4 0
3 years ago
Read 2 more answers
Is this a function. ?
marusya05 [52]
No because one of the X’s has multiple Y’s
5 0
3 years ago
Read 2 more answers
A scatter Plot was made to show the number of homes in a town based on the year. The line of best fit drawn on the graph is y =
jekas [21]

Answer:

y = 2,305 homes

Step-by-step explanation:

2015-1995 = 20

84*20 = 1,680

1,680 + 625 = 2,305

Therefore, there were 2,305 homes in the town in 2015.

4 0
4 years ago
Am I correct on question #6?
pashok25 [27]

Option A:

\tan(105^\circ)=-(2+\sqrt{3})

Solution:

<u>To evaluate tan(105)°:</u>

105° can be written as sum of 60° and 45°.

tan(105)° = tan(45 + 60)°

Using the summation identity:

$\tan (x+y)=\frac{\tan (x)+\tan (y)}{1-\tan (x) \tan (y)}

$\tan \left(105^{\circ}\right)=\frac{\tan \left(45^{\circ}\right)+\tan \left(60^{\circ}\right)}{1-\tan \left(45^{\circ}\right) \tan \left(60^{\circ}\right)}

We know that, tan(45)° = 1 and tan(60)° = √3

Substitute this in the above equation.

              $=\frac{1+\sqrt{3}}{1-1 \cdot \sqrt{3}}

              $=\frac{1+\sqrt{3}}{1-\sqrt{3}}

To rationalize the denominator multiply by the conjugate \frac{1+\sqrt{3}}{1+\sqrt{3}}.

              $=\frac{(1+\sqrt{3})(1+\sqrt{3})}{(1-\sqrt{3})(1+\sqrt{3})}

Using exponent formula: a^{b} \cdot a^{c}=a^{b+c} and (x-y)(x+y)=x^2-y^2

              $=\frac{(1+\sqrt{3})^2}{(1^2-(\sqrt{3})^2)}

Using exponent formula: (a+b)^{2}=a^{2}+2 a b+b^{2}

              $=\frac{1^{2}+2 \cdot 1 \cdot \sqrt{3}+(\sqrt{3})^{2}}{1-3}

              $=\frac{4+2 \sqrt{3}}{-2}

              $=\frac{2(2+ \sqrt{3})}{-2}

              =-(2+\sqrt{3})

\tan(105^\circ)=-(2+\sqrt{3})

Hence option A is the correct answer.

6 0
4 years ago
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