Standard form is written Ax + By = C where A, B, and C are all integers.
In other words, no fractions.
Also, the A or the coefficient of the x term must be positive.
The only thing we need to do is add 7x to both sides to get 7x + y = -1.
So 7x + y = -1 is our answer.
Lateral area of triangular prism = (a+b+c)h where a, b and c are the sides of the triangular base, h is the height.
LA= (a+b+c)h=
a=4
b=6
c=?
c=9
h=8
c=√6²+4²=√80 or approximately 9
you should get An Area= (4+6+√80)8
LA= 80+8√80
<span>Find
the values of a and b that make f continuous everywhere. f(x) = x^2 − 4
/ x − 2 if x < 2 ax^2 − bx + 3 if 2 ≤ x < 3 4x − a + b if x ≥ 3
</span>
a=7/12
b=13/2
Answer:
AC = 2.44
Step-by-step explanation:
Reference angle = 26°
Opposite side = AC = ?
Adjacent side = BC = 5
Applying TOA, we have:
Tan 26 = opp/adj
Tan 26 = AC/5
multiply both sides by 5
Tan 26 × 5 = AC
AC = 2.44 (nearest hundredth)
Answer: The answer is (B) ∠SYD.
Step-by-step explanation: As mentioned in the question, two parallel lines PQ and RS are drawn in the attached figure. The transversal CD cut the lines PQ and RS at the points X and Y respectively.
We are given four angles, out of which one should be chosen which is congruent to ∠CXP.
The angles lying on opposite sides of the transversal and outside the two parallel lines are called alternate exterior angles.
For example, in the figure attached, ∠CXP, ∠SYD and ∠CXQ, ∠RYD are pairs of alternate exterior angles.
Now, the theorem of alternate exterior angles states that if the two lines are parallel having a transversal, then alternate exterior angles are congruent to each other.
Thus, we have
∠CXP ≅ ∠SYD.
So, option (B) is correct.