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3 years ago

Consider: f(x) = 1/2(3)^x and g(x) = -1/2(3)^-x

Mathematics

1 answer:

svet-max [94.6K]3 years ago

3 0

Answer:

Step-by-step explanation:

C: os valores de saída são refletidos no eixo xe os valores da entrada são refletidos no eixo y.

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Find the average rate of change of f(x)=2x^2-7x from x=2 to x=5

m_a_m_a [10]

Answer:

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [2, 5 ]

f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15

f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus

average rate of change = $\frac{15-(-6)}{5-2}$ = $\frac{21}{3}$ = 7

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3 years ago

-34-r=-7(8r-3) what is the work and answer

NeX [460]

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2 years ago

Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7

Dima020 [189]

Answer:

The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ .

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

$\dfrac{\textrm factor of P}{\textrm factor Q}$ ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial , P = -7 , Q = 4

Now , $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$

I.e $\dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}$ = $\frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }$

Or, The rational zero are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$

Hence The rational zero of the polynomial are $\pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1$ . Answer

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3 years ago

What two equivalent ratios for 30 to 6

alexgriva [62]

Two equivalent ratios for 30 to 6 can be 15 to 3 or 45 to 9

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2 years ago

151 1/2 over 25 1/4=6

Setler79 [48]

Answer: 6 = 6

Step-by-step explanation:

8 0

2 years ago