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nadya68 [22]
3 years ago
14

Triangle A B C is shown. Angle B C A is a right angle. The length of hypotenuse A B is 5, the length of B C is 3, and the length

of A C is 4. What is the length of the side opposite Angle B? 3 units 4 units 5 units 6 units

Mathematics
1 answer:
svetoff [14.1K]3 years ago
5 0

The side opposite to angle B is the side that does not contact with angle B.

In this attached image, you can see better that sides AB and BC is in contact with angle B. So, the opposite side to angle B is AC.

Therefore, the lenght of the side opposite to angle B is 4 units.

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Josef has 35 square feet of tiles. He cuts 15 of those tiles in half. How many square feet of tiles does Josef have now? Explain
Tanya [424]

Answer:

50

Step-by-step explanation:

35 +15 =50  15 dived by 2 = 7.5 x 2 =15 + 35 = 50

7 0
3 years ago
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you are baking muffins for your class. there are 17 total students in your class and you have baked 5 muffins. write and solve a
Tresset [83]
For your first answer 2=x+5/17 your second answer is 29. This is because "x" is the number that you need to bake which is 29. Therefore, 31/17=2
4 0
3 years ago
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3. Sophie and Jackie each have a collection of baseball cards, Jackie has 5 more cards than
IRISSAK [1]

Answer:

Sophie has 12.5 cards

Step-by-step explanation:

Let

x -----> number of cards Sophie has

y -----> number of cards Jackie has

we know that

x+y=30 -----> equation A  

y=x+5 -----> equation B

Solve by substitution

Substitute equation B in equation A and solve for x

x+(x+5)=30

2x=30-5

x=12.5 cards

Note I assume the problem was invented without taking into account the result, because the amount of cards should be a whole number

5 0
3 years ago
Can anyone help with this?
sergeinik [125]

Answer:

The answer is B and D.

Step-by-step explanation:

I hope this helped and if it did I would appreciate it if you marked me brainliest. Thank you and have a nice day!

4 0
3 years ago
In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>​
Lemur [1.5K]

In both cases,

AB^2=AD^2

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

(4x+7)^2=(6x-3)^2

16x^2+56x+49=36x^2-36x+9

20x^2-92x-40=0

5x^2-23x-10=0

(5x+2)(x-5)=0\implies\boxed{x=5}

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

(4x^2-18x-10)^2=(x^2+x+4)^2

16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16

15x^4-146x^3+235x^2+352x+84=0

(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}

(again, omit the solutions that would give a negative length for either AB or AD)

7 0
3 years ago
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