Given the relationship T^2 = A^3, to compare the values of the orbital periods of X and Y, it would be easier to assign values. Since the Planet Y's distance A is twice that of Planet X's distance A, this can be shown below:
For Planet X (where A = 2):
T^2 = 2^3
T = 2.828
For Planet Y (where A = 4)
T^2 = 4^3
T = 8
Therefore, planet Y's orbital period is larger by (8/2.828) = 2.83 times.
Answer:
Step-by-step explanation:
Line passes through (0,0) and (-1,4) .
Slope = -4
Equation of line is : y - 0 = - 4(x - 0)
y = - 4x
Answer: D
Step-by-step explanation:
5²-11=14
6^2-11= 25
14>25
as the question asks for something lower than 25 not lower/equal to the answer is D.