Question

Solve for: ∫_(-1)^1 x^3+1/2 dx

Answer 1

Answer:

$\int _{\left(-1\right)}^1\frac{x^3+1}{2}dx$

$=\frac{1}{2}\cdot \int _{\left(-1\right)}^1x^3+1dx \Leftarrow(take \: constant\: out)$

$=\frac{1}{2}\left(\int _{\left(-1\right)}^1x^3dx+\int _{\left(-1\right)}^11dx\right) \Longleftarrow (Sum\:Rule)$

$\int _{\left(-1\right)}^1x^3dx=0$

$\int _{\left(-1\right)}^11dx=2$

$=\frac{1}{2}\left(0+2\right)$

$=1$

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OAmalOHopeO

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