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Lunna [17]
3 years ago
13

Solve for: ∫_(-1)^1 x^3+1/2 dx

Mathematics
1 answer:
Rudiy273 years ago
4 0

Answer:

\int _{\left(-1\right)}^1\frac{x^3+1}{2}dx

=\frac{1}{2}\cdot \int _{\left(-1\right)}^1x^3+1dx \Leftarrow(take \: constant\: out)

=\frac{1}{2}\left(\int _{\left(-1\right)}^1x^3dx+\int _{\left(-1\right)}^11dx\right) \Longleftarrow (Sum\:Rule)

\int _{\left(-1\right)}^1x^3dx=0

\int _{\left(-1\right)}^11dx=2

=\frac{1}{2}\left(0+2\right)

=1

❃❃❃❃❃❃❃❃❃❃❃

<h3>OAmalOHopeO</h3>

❃❃❃❃❃❃❃❃❃❃❃

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