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Fiesta28 [93]
3 years ago
14

Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all

the possible values, separated by commas.
Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

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Leni [432]
Y=-3x+2:
Already in slope intercept form
Graph by plotting a point on (0,2)
Then move 3 points up and 1 to the right and plot the point and keep doing that a couple times

-3x-y=-2:
Add -3x on both sides
The result would be
-y=3x-2
Divide everything by negative 1
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Both equations are the same so they are the same line
8 0
3 years ago
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olga2289 [7]
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3 years ago
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Which is the exponential form of log8 x=3
Ostrovityanka [42]

Answer:

x = 8^3

Step-by-step explanation:

To rewrite an equation with logs in exponential form, you need to know

logb(a) = m  is equivalent to   a= b^m


So given    log8 (x) = 3   is equivalent to   x = 8^3

                     

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3 years ago
Determine which side is the smallest in the diagram
AnnyKZ [126]

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5 0
3 years ago
In ΔMNO, m = 780 inches, o = 760 inches and ∠O=164°. Find all possible values of ∠M, to the nearest degree.
Mademuasel [1]

Answer:

So the answer is both

180 and 328 (but it may or may not show you "not possible, if so, then you got it right)

Step-by-step explanation:

SinA/a= SinB/b

1. SinM/780 = Sin164/760

2. 780sin164/760 = 0.2828909704

3. M = sin^-1 (0.2828909704)= 16.4328229 or 16

Check for possibility

180-16= 164

164 + 16= 180 (not possible)

164 + 164= 328 (not possible)

4 0
2 years ago
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