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Fiesta28 [93]
3 years ago
14

Let omega be a complex number such that omega^3 = 1. Find all possible values of {1}{1 + \omega} + {1}{1 + \omega^2}. Enter all

the possible values, separated by commas.
Mathematics
1 answer:
Norma-Jean [14]3 years ago
8 0

Answer:

1 is Answer.

Step-by-step explanation

\frac{1}{1+omega^{2} } + \frac{1}{1+omega }\\

= \frac{(-1)*(omega + 1)}{omega^{2}  }

As we know that ω²+ω+1=0

Thus putting in above equation, we get

= \frac{1}{(-1)*omega } + \frac{1}{(-1)*omega^{2}  }

Rearranging and simplifying:

= \frac{-1}{omega } + \frac{-1}{omega^{2}  }

= \frac{(-1)*(omega + 1)}{omega^{2}  }

= \frac{(-1)*(- omega^{2} )}{omega^{2}  }

= 1 Answer

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Answer:

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Goshia [24]
I'll help you out with 3 questions.
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