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kozerog [31]
3 years ago
12

- Aidan buys used bicycles, fixes them up, and sells them. His average cost to buy and fix each bicycle is $27. He also incurred

a one- time cost of $960 to purchase tools and a small shed to use as his workshop. He sells bikes for $67 each. How many bicycles does Aiden have to sell to reach the "break-even" point?​
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer: Adrian will need to fix 25 bikes to reach a break even point.

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Simplify- -126 x*2 y*7 z*3 w
worty [1.4K]

the answer is 5 2 9 2

really all you have to do is multiply 126 * 2 * 7 * 3

then all that's next is to just put the letters in the order they were originally at the end of the answer

7 0
3 years ago
Search results for "A bottle of root beer contains 4/5 of a liter how much root beer is in 3 bottles"
NikAS [45]
For this all you have to do is take the numerator and multiply it by 3
4*3=12
3 bottles contain 2.4 liters of root beer.
or
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3 0
3 years ago
In circle N, KL ≅ ML.<br><br> What is the measure of ?<br> 77°<br> 90°<br> 132°<br> 154°
Alexeev081 [22]
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6 0
3 years ago
Read 2 more answers
Which of the following relation is a function? A.{(0,2),(3,6),(0,1),(6,3)}B. {(1,2),(6,7),(9,9),(3,7)} C.{(4,5),(1,3),(5,5),(4,0
valkas [14]
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6 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

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Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
2 years ago
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