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grin007 [14]
3 years ago
9

What is the rule if: x______yx y 3 1 9 3 15 5

Mathematics
1 answer:
kicyunya [14]3 years ago
8 0

Answer:

y - 1 = (1/3)(x - 3)

Step-by-step explanation:

By inspection we see that if x increases by 6, y increases by 2.  Thus, the slope of the line connecting 2 or more of these points is m = 2/6, or m = 1/3.

Using the point-slope formula y - k = m(x - h), we substitute 1/3 for m, 3 for h and 1 for k, obtaining:

y - 1 = (1/3)(x - 3)

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Slope- intercept equation from graph.
damaskus [11]

Answer:

y=mx+b

Step-by-step explanation:

y=1/2+-2

5 0
3 years ago
What is the value of x?
soldi70 [24.7K]

Answer:

5\sqrt{3}

Step-by-step explanation:

A triangle with angles of 30-60-90 will always have sides that measure in the following proportions:

The side opposite the 30* angle = a

The side opposite the 60* angle = a\sqrt{3}

The side opposite the 90* angle = 2a

(I used "a" here because your question uses "x" and I don't want to confuse things, but usually people use "x" rather than "a")

They gave us that the hypotenuse (the side opposite the 90* angle) is 10, from there we can figure out the other sides:

Since the side opposite 90* is 2a, and 2a = 10, divide 10 by 2 and you get a = 5.

Once we know what "a" is, we can fill in the rest:

30* = 5

60* = 5\sqrt{3}

90* = 10

3 0
3 years ago
Could someone tell me if it's okay? <br><br> Plz
Leokris [45]

Answer:

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7 0
3 years ago
Prove the divisibility of the following numbers: 5^23−5^21 by 24
vodka [1.7K]
5^23 - 5^21 = 5^(21+2) - 5^21
5^23 - 5^21 = 5^21*5^2 - 5^21*1
5^23 - 5^21 = 5^21*(5^2 - 1)
5^23 - 5^21 = 5^21*(25 - 1)
5^23 - 5^21 = 5^21*24
5^23 - 5^21 = 24*5^21
5^23 - 5^21 = 24*k

The original number is in the form 24k where k = 5^21, so this proves that the original number is a multiple of 24

6 0
4 years ago
Read 2 more answers
F(x) = 4√(2x³-1)<br> F'(x) =....?
icang [17]
y= \sqrt[4]{(2x^3-1)} \\ y^4=2x^3-1 \\ 2x^3=y^4+1 \\ x^3= \frac{y^4+1}{2} \\ x= \sqrt[3]{\frac{y^4+1}{2}}

Therefore, F'(x) = \sqrt[3]{\frac{y^4+1}{2}}
7 0
4 years ago
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