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alekssr [168]
4 years ago
13

F(x) = 4√(2x³-1) F'(x) =....?

Mathematics
1 answer:
icang [17]4 years ago
7 0
y= \sqrt[4]{(2x^3-1)} \\ y^4=2x^3-1 \\ 2x^3=y^4+1 \\ x^3= \frac{y^4+1}{2} \\ x= \sqrt[3]{\frac{y^4+1}{2}}

Therefore, F'(x) = \sqrt[3]{\frac{y^4+1}{2}}
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