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jeka94
3 years ago
13

what is the maximum number of amino acids that can be specified by a codon consisting of a sequence of four bases

Biology
1 answer:
vichka [17]3 years ago
8 0

Answer:

64.

Explanation:

It is 64 because there are 20 amino acids with four bases ( A,T,C and G).

and genetic code can be read in triplets and also the four bases can occupy the positions. Eachh amino acid can be coded by the triplet codons. A triplet codon shows three nucleotides of the mRNA template that can code for amino acid

Therefore the number of codons is 4×4×4= 64.

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When does the total number of chromosomes get reduced from 46 pairs to 23 individual chromosomes? View Available Hint(s) When do
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Answer:

23 pairs of chromosomes (46 individual chromosomes) are redued to 23 individual chromosomes in meiosis I.

During Meiosis I

Explanation:

Meiosis is a type of cell division that results in four daughter cells with each having half the number of chromosomes as in the parent cell. During meiosis, cell division occurs twice because before the two halves of a duplicated chromosome (sister chromatids) is separated, it still needs to separate homologous pair of chromosomes, which is a similar but non-identical pair of chromosomes received from both parent. Hence, meiosis occurs in a two step division process; Meiosis I and Meiosis II.

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Homologous pairs, not individual chromosomes (23 pairs in number) line up at the metaphase plate for separation during metaphase I.

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After cytokinesis (division of the cytoplasm) in meiosis I, two daughter cells are produced and each now possesses 23 individual chromosomes (haploid) different from the parental 23 pairs (diploid).

N.B: Sister chromatids separate in the anaphase of meiosis II, where each chromatid is counted as an individual chromosome.

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