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Natali5045456 [20]
3 years ago
11

1. Explain why n root a^n= |a| when n is even, but not when n is odd.

Mathematics
1 answer:
kogti [31]3 years ago
8 0

Step-by-step explanation:

In the expression a^n, for integer values of n greater than 1, there are n factors. For example, a^2 = a * 2 (2 factors), a^3 = a * a * a (3 factors), etc.

For a non-negative value of a, a^n is non-negative for all values of n.

If a is negative, and n is even, then a^n is non-negative.

If a is negative, and n is odd, then a^n is negative.

|a| is non-negative for all values of a.

sqrt_n(a^n) is negative for negative a and odd n, but |a| is always non-negative, so sqrtn(a^n) cannot equal |a| for odd n.

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Answer:

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Answer:

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Step-by-step explanation:

an = 2.5n -0.2

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Ella has 0.5 lbs of sugar. How much water should she add to make the following concentrations? Tell Ella how much syrup she will
HACTEHA [7]

Ella has to add 32.833 lbs of water to get 33.333 lbs of syrup.

<u>Solution:</u>

Ella has 0.5 lbs of sugar. Let x lbs be the amount of water Ella should add to get the 1.5% of syrup,

\Rightarrow0.5\text{ lbs }- 1.5\%

\Rightarrow x+0.5\text{ lbs }- 100\%

On writing the proportion,

\Rightarrow\dfrac{0.5}{x+0.5}=\dfrac{1.5}{100}\\ \\\Rightarrow0.5\cdot 100=(x+0.5)\cdot 1.5\\ \\\Rightarrow50=1.5x+0.75\\ \\\Rightarrow1.5x=50-0.75\\ \\\Rightarrow1.5x=49.25\\ \\\Rightarrow x=\dfrac{49.25}{1.5}\approx 32.833\ lbs

To get 1.5% syrup Ella should add 32.833 lbs of water. The total weight of syrup is 33.333 lbs.

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Step-by-step explanation:

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rusak2 [61]

Answer:

An inequality compares two or more variables by using the <, >, ≤, or ≥ signs.

The number of hours Lourdes will have to jog is 0.4 hours

From the given parameters:

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If Lourdes can jog averagely at the speed of 3.75 mph

Then,

the inequality that can represent the information can be written as:

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Solving the inequality;

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Making (x) the subject of the formula, we have:

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Therefore, we can conclude that the number of  hours lourdes will have to jog is 0.4 hours

Step-by-step explanation:

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