Answer:
l=0.1401P\\
w =0.2801P
where P = perimeter
Step-by-step explanation:
Given that a window is in the form of a rectangle surmounted by a semicircle.
Perimeter of window =2l+\pid/2+w

Or 
To allow maximum light we must have maximum area
Area = area of rectangle + area of semi circle where rectangle width = diameter of semi circle


Hence we get maximum area when i derivative is 0
i.e. 

Dimensions can be

Answer:Please include images of the graphs!
2/1 is the fraction always as a whole number the whole number goes on top and always the 1 goes on bottom for every whole number Hope that helped have a good day! :)
#5 is 4, #6 is graph A, and #7 is graph B. I hope this helped, Please mark as brainliest because I am 3 more away from the next level.
Answer:
I believe your answer is the second option. My apologies if it is wrong.
Step-by-step explanation: