Based on function transformations, the graph of y= cos(2θ), is the same as the graph of <span>y= cos(θ), with a component B of 2, in which case, it means the period is the only thing that differs

well the period for this function will then be </span> $\bf \cfrac{2\pi }{B}\iff \cfrac{2\pi }{2}\implies \pi$

so, the graph of is, the same as y= cos(θ), just shrunk by half horizontally

7 0

3 years ago

Which equation is y = 3(x – 2)2 – (x – 5)2 rewritten in vertex form?

Alenkinab [10]

Y= 3( x -2 )² - ( x-5 )² = 3 ( x² - 4 x + 4 ) - ( x² - 10 x + 25 ) =
= 3 x² - 12 x + 12 - x² + 10 x - 25=
= 2 x² - 2 x - 13 =
= 2 ( x² - x + 1/4 - 1/4 ) - 13 =
= 2 ( x - 1/2 )² - 1/2 - 26/2 = 2 ( x - 1/2 )² - 27/2
Answer: D)

4 0

3 years ago