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Dmitry_Shevchenko [17]
3 years ago
9

Sofia works at Cowboy Corner. She receives 10% commission on all of the cowboy hats she sells in a month. If Sofia sells $545 in

total sales, what is her commission? (include steps or explanation in ur answer)
Mathematics
1 answer:
marta [7]3 years ago
7 0

Answer:

$54.50

Step-by-step explanation:

10% = 10/100

=545 × 10/100

=5450/100

=54.5

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4 0
3 years ago
Find the perimeter of a square plot whose is 100m<br><br><br><br><br>please anyone help me... ​
hichkok12 [17]

Answer:

400m(if the length of sides is 100m)

Step-by-step explanation:

4L

4×100

=400m

7 0
3 years ago
If you see a snake the best thing to do is walk away if it’s chasing you DO NOT RUN this might seem crazy but let it go on you a
Aliun [14]

Answer:

So, is this just a 'just you should know' thing?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Historically, a certain region has experienced 92 thunder days annually. (A "thunder day" is day on which at least one instance
DiKsa [7]

Answer:

We conclude that the mean number of thunder days is less than 92.

Step-by-step explanation:

We are given that Historically, a certain region has experienced 92 thunder days annually.

Over the past fifteen years, the mean number of thunder days is 72 with a standard deviation of 38.

<u><em>Let </em></u>\mu<u><em> = mean number of thunder days.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 92 days     {means that the mean number of thunder days is more than or equal to 92}

Alternate Hypothesis, H_A : \mu < 92 days     {means that the mean number of thunder days is less than 92}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of thunder days = 72

             s = sample standard deviation = 38

            n = sample of years = 15

So, <u><em>test statistics</em></u>  =  \frac{72-92}{\frac{38}{\sqrt{15} } }  ~ t_1_4

                               =  -2.038

The value of z test statistics is -2.038.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the t table gives critical value of -1.761 at 14 degree of freedom for left-tailed test.

Since our test statistics is less than the critical value of t as -2.038 < -1.761, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean number of thunder days is less than 92.

7 0
3 years ago
Compare A and B in three​ ways, where Aequals=52,193 is the number of deaths due to a deadly disease in the United States in 200
andreyandreev [35.5K]

Answer:

a. The ratio of A to B is 2.92 : 1

b. The ratio of B to A is 1 : 2.92

c. A is 292% of B

Step-by-step explanation:

A = 52193

B = 17878

a. The ratio of A to B is: 52193 : 17878

To get the ratio in lower form, divide A with B (since it is the smallest of the two value) and the result is:

2.92 : 1

b. The ratio of B to A is: 17878 : 52193

1 : 2.92

c. The percentage of A to B is:

= \frac{A}{B}  * 100\\= \frac{52193}{17878}  * 100\\= \frac{5219300}{17878} \\= 291.939814297\\= 292%

6 0
3 years ago
Read 2 more answers
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