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Free_Kalibri [48]
2 years ago
12

The bacteria in a culture double every day. Which function can be used to find the number of bacteria n after d days if there ar

e initially 75 bacteria?
On=2(75)
O n = 75(g)
On = 75(2)
On= (75)"

Mathematics
1 answer:
Nikolay [14]2 years ago
3 0

Answer:

n = 75(2)^d

Step-by-step explanation:

Mathematically, we have the general form of an exponential equation as follows;

y = I(1 + r)^x

where I is the initial value

r is the rate percentage

x is the number of time

From the question, the bacteria population doubles

This mean it increases by 100%

100% = 1

add this to the initial 1, and we have 2

Replace I with the number 75

And d represents the days

so we have;

n = 75(2)^d

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Comment
I'm going to take a guess at this and say what you meant is  2401 = 7^(6 - 2x)

Step One
Find out the power of 7 that will equal 2401. 
You could do it like this.
7^y = 2401 and just guess at some values.

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Step 2 
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