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yuradex [85]
3 years ago
8

The diameter of a circle has endpoints P(-12, -4) and Q(6, 12).

Mathematics
1 answer:
nexus9112 [7]3 years ago
3 0

9514 1404 393

Answer:

  (x +3)² +(y -4)² = 145

Step-by-step explanation:

The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...

  A = (P +Q)/2

  A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2

  A = (-3, 4)

The equation of the circle for some radius r is ...

  (x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle

The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...

  (6 +3)² +(12 -4)² = r² = 9² +8²

  r² = 81 +64 = 145

Then the equation of the circle is ...

  (x +3)² +(y -4)² = 145

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Answer:

See Explanation

Step-by-step explanation:

(a) Proof: Product of two rational numbers

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Let the two rational numbers be A and B.

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B = \frac{2}{3}

The product:

A * B = \frac{1}{2} * \frac{2}{3}

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A * B = 1 * \frac{1}{3}

A * B = \frac{1}{3}

Proved, because 1/3 is rational

(b) Proof: Quotient of a rational number and a non-zero rational number

Using direct proofs.

Let the two rational numbers be A and B.

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A = \frac{1}{2}

B = \frac{2}{3}

The quotient:

A / B = \frac{1}{2} / \frac{2}{3}

Express as product

A / B = \frac{1}{2} / \frac{3}{2}

A / B = \frac{1*3}{2*2}

A / B = \frac{3}{4}

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(c) x + y is rational (missing from the question)

Using direct proofs.

Let x and y be

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x = \frac{1}{2}

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x + y = \frac{7}{6}

Proved, because 7/6 is rational

<em>The above proof works for all values of A, B, x and y; as long as they are rational values</em>

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Answer:

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Use the factor theorem to determine whether the first polynomial is a factor of the second polynomial
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