Answer:
70
Step-by-step explanation:
= First term = 
= Common difference = 
= Number of terms = 20
Sum of arithmetic progression is given by
![S=\dfrac{n}{2}[2a_1+(n-1)d]\\\Rightarrow S=\dfrac{20}{2}\times (2\times \dfrac{1}{3}+(20-1)\dfrac{1}{3})\\\Rightarrow S=70](https://tex.z-dn.net/?f=S%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a_1%2B%28n-1%29d%5D%5C%5C%5CRightarrow%20S%3D%5Cdfrac%7B20%7D%7B2%7D%5Ctimes%20%282%5Ctimes%20%5Cdfrac%7B1%7D%7B3%7D%2B%2820-1%29%5Cdfrac%7B1%7D%7B3%7D%29%5C%5C%5CRightarrow%20S%3D70)
The sum of the first 20 terms of the arithmetic sequence is 70.
336......?? find the area of cross section and than multiply with the lenght
4:2 can represented as 4 / 2. Or also 2.
30 / 2 = 15
Answer:
Part A: 2D + 3 = A
Note: I have likely given you the answer to the whole problem. See below.
Step-by-step explanation:
Givens
- Alan = A
- Bruce = B
- Cecil = C
- Dylan = D
Comment
You have to pay the most attention to Alan and Bruce. Once you have equations for those two. Cecil's weight is just the sum of those two.
<em>Alan</em>
Alan = Twice*Dylan + 3 or
A = 2*D + 3
<em>Bruce</em>
Bruce = three * Dylan - 12
B = 3*D - 12
<em>Cecil</em>
Cecil = Alan + Bruce
C = A + B
Note
The last equation shows you how to combine the first two.
C = A + B
A = 2D + 3
B = 3D - 12
C = 2D + 3 + 3D - 12
C = 5D - 9
(0,2) because following the formula x,y, the 2 is the y, while the 0 is the x.
