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vivado [14]
3 years ago
8

See file attached below:

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

Goodluck my dude.

Step-by-step explanation:

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A friend of yours was interested in determining whether the news media noticed campus events. Your friend decided to do a conten
anygoal [31]

The inference is that the person will tell the friend that he did manifest coding and he should have recorded the base.

<h3>What is an inference?</h3>

The options are:

He did manifest coding.

He did latent coding.

He should have recorded the base.

He did manifest coding and he should have recorded the base.

It should be noted that an inference simply means the conclusion that can be deduced based on the information given.

In this case, the friend was interested in determining whether the news media noticed campus events and decided to do a content analysis of the local paper.

Therefore, the the person will tell the friend that he did manifest coding and he should have recorded the base.

Learn more about inference on:

brainly.com/question/25280941

#SPJ12

8 0
2 years ago
Read 2 more answers
Slope is 2 and (−1, 6) is on the line; point-slope form
MissTica

Answer:

y-6=2(x-(-1))

Or simplified:

y-6=2(x+1)

Step-by-step explanation:

use the formula: y-y1=m(x-x1)

8 0
3 years ago
PLZ HELP I PROMISE I WILL GIVE BRAINLIEST!!!! ASAP
irga5000 [103]

Answer:

4c^{7}d^{13}

Step-by-step explanation:

(2cd^{4} )^{2} *(cd)^{5}

4c^{2}d^{8} *c^{5} d^{5}

4c^{7}d^{13}

4 0
3 years ago
What u.s. customary unit is closest to a kilogram???
iren2701 [21]
Pound is closest to a kilogram
4 0
3 years ago
The limit as h approaches 0 of (e^(2+h)-e^2)/h is ?
Whitepunk [10]
<span>If you plug in 0, you get the indeterminate form 0/0. You can, therefore, apply L'Hopital's Rule to get the limit as h approaches 0 of e^(2+h),
which is just e^2.
</span><span><span><span>[e^(<span>2+h) </span></span>− <span>e^2]/</span></span>h </span>= [<span><span><span>e^2</span>(<span>e^h</span>−1)]/</span>h

</span><span>so in the limit, as h goes to 0, you'll notice that the numerator and denominator each go to zero (e^h goes to 1, and so e^h-1 goes to zero). This means the form is 'indeterminate' (here, 0/0), so we may use L'Hoptial's rule:
</span><span>
=<span>e^2</span></span>
3 0
3 years ago
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