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OlgaM077 [116]
4 years ago
14

Triangle PQR has sides measuring 9 feet and 10 feet and a perimeter of 24 feet. What is the area of triangle PQR? Round to the n

earest square foot.
square feet

Mathematics
2 answers:
GalinKa [24]4 years ago
6 0

Answer:

22 square foot

Step-by-step explanation:

Consider PQR be a triangle, such that PQ=9 feet, PR=10 feet.

Now, Perimeter of triangle=24

⇒Sum of all the sides=24

⇒PQ+PR+QR=24

⇒9+10+QR=24

⇒QR=5 feet

Also, s=\frac{a+b+c}{2}=\frac{9+10+5}{2}=12

Area of triangle A=\sqrt{s(s-a)(s-b)(s-c)}

=\sqrt{12(12-9)(12-10)(12-5)}

=\sqrt{12(3)(2)(7)}

=\sqrt{504}

=22.44

≈22sq foot

thus, area of triangle=22 square foot.

spin [16.1K]4 years ago
3 0
The answer is 22 square feet :) hope this helps
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Step-by-step explanation:

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According to the U.S. Census Bureau, 42% of men who worked at home were college graduates. In a sample of 480 women who worked a
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Answer:

1) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

The point estimate for the proportion of college graduates among women who work at home is 0.327

2) 0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

Step-by-step explanation:

For this case we have the following info given:

X = 157 represent the women who worked at home who were college graduates

n = 480 the sample size selected

Part 1

In order to find the proportion of college graduates among women who work at home and we can use the following formula:

\hat p=\frac{X}{n} = \frac{157}{480}= 0.327

The point estimate for the proportion of college graduates among women who work at home is 0.327

Part 2

Construct an 80% confidence interval for the proportion of women who work at home who are college graduates. Round the answer to three decimal places. An 80% confidence interval for the proportion of women who work at home Is < p <

The confidence interval for the true proportion would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 80% confidence interval the value for the significance is\alpha=1-0.8=0.2 and \alpha/2=0.1, the critical value would be given by:

z_{\alpha/2}=0.539

And replacing we goot:

0.327 - 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.315

0.327 + 0.539 \sqrt{\frac{0.327(1-0.327)}{480}}=0.339

The 80% confidence interval is given by (0.315; 0.339)

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