Answer:A
Step-by-step explanation: The first few square numbers are:
1
,
4
,
9
,
16
,
25
,
36
,
49
,
√
1
=
1
√
4
=
2
√
9
=
3
√
16
=
4
√
25
=
5
√
36
=
6
w
w
w
w
w
w
←
√
40
lies here
√
49
=
7
Therefore
√
40
is between
6
and
7
Answer:
They rode 14 miles before replacing each horse
Step-by-step explanation:
We will be working under the assumption that all three riders sat on one horse at a time and rode it while the other horses rested.
From the problem, we can understand that the horses were each ridden for the same distance. This means that to get the total distance a horse rode before it was changed, we can divide the total distance by the number of horses that were used for the journey.
Distance each horse rode = 182/ 13 = 14 miles.
Therefore, each horse was ridden for 14 miles before it was changed.
Building time :
4c + 6a < = 120
testing time :
4c + 4a < = 100
20 child bikes and 6 adult bikes...c = 20 and a = 6
sub into both equations
4c + 6a < = 120
4(20) + 6(6) < = 120
80 + 36 < = 120
116 < = 120 (correct)
4c + 4a < = 100
4(20) + 4(6) < = 100
80 + 24 < = 100
104 < = 100 (incorrect)
ur answer : No, because the bike order does not meet the restrictions of 4c + 6a < = 120 and 4c + 4a < = 100
<em>Make the unknown numerator be x and unkown denominotor be y</em>
<em>We have : 7 - </em>
= 6
=> = 7 - 6
= 
<em>So we need to fill in the box :</em>
<em>If the answer is helpful, Brainliest please!</em>
Answer:
60% increase
Step-by-step explanation:
152 - 95 = -57
57 / 95 = 0.6
0.6 x 100 = 60
