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3 years ago

7

Please help me please help me please please someone can please help me this is way too hard please please please please please p

lease please someone please help me

1 answer:

anzhelika [568]3 years ago

5 0

Answer:1 0.05806644 2 64.3818067 m2 3 10.8696557 m2 4 80.2682266 m2 0.13935456 m2 and 15.7935168 m2

Step-by-step explanation:

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A footbridge is 5 feet wide and is built with wood planks that are 6 inches wide. How many planks wide is the path?

Ede4ka [16]

Here we have to know the conversion between feet and inches.

1 Feet = 12 inches (This is given and is to be known)

So the 5 feet wide footbridge when converted to inches would be about 5*12 = 60 inches

The width of the footbridge in inches = 60 inches

Each wooden plank is 6 inches,

So the number of wooden planks that are required to build the foot bridge of 60 inches = 60/6 = 10 planks

Hence, the path path is 10 planks wide

7 0

3 years ago

The Lewis family is building a circular swimming pool if the radius of the pool is 9 feet what is it’s circumference use TT =3.1

zzz [600]

Answer:

C =56.52 ft

Step-by-step explanation:

The circumference is found by

C = 2*pi*r where r is the radius

C = 2*3.14 * 9

C =56.52 ft

5 0

3 years ago

Can someone show me how to work out this example?<br><br><br> (5+44+182−20−10)÷(2+5)

lora16 [44]

Answer:

approximately 35.9

Step-by-step explanation:

(5+44+182-20-10)÷(2+5)

(99+182-20-10)÷(7)

(281-20-10)÷(7)

(261-10)÷÷(7)

(251)÷(7)

approximately 35.9

6 0

3 years ago

The classes At the middle school want to rise money the 6 grade runs a bake sale 5 hours and makes 170 the 7 grade sets up a dru

kaheart [24]

Sixth grade
Because if you divide their total profit by the total amount of hours they worked, you would find that the sixth grade's income per hour is the highest.
Sixth grade: 170÷5=34
Seven grade: 112÷4=28
Eighth grade: 192÷6=32

8 0

3 years ago

Answers fast please. 1.) y=x−63x+2y=8 Use the substitution method. A.) (4, −2) B.) (14, 8) C.) (0, −6) D.) (3, −3) 2.) What is t

GrogVix [38]

<u>QUESTION 1</u>

The given system of equation is

$y=x-6...eqn1$

and

$3x+2y=8...eqn2$

Let us substitute equation (1) into equation (2) to get,

$3x+2(x-6)=8$

We expand the bracket to get,

$3x+2x-12=8$

We simplify to get.

$5x-12=8$

We group like terms to get

$5x=8+12$

$\Rightarrow 5x=20$

$\Rightarrow x=4$

We now substitute $x=4$ in to equation (1) to obtain,

$y=4-6=-2$

The correct answer is option A.

<u>QUESTION 2</u>

The given system of equations is

$y-x=9...eqn1$

and

$10+2x=-2y...eqn2$

We make y the subject in equation (2) to get,

$y=-x-5..eqn3$

We put equation (3) into equation (1) to obtain,

$-x-5-x=9$

We group like terms to get,

$-x-x=9+5$

This implies that,

$-2x=14$

We divide through by $-2$ to get,

$x=-7$

Hence the x-coordinate is $-7$

<u>QUESTION 3</u>

The given system is

$y=3x-1..eqn1$

and

$x-y=-9...eqn2$

We make $x$ the subject in equation (2) to get,

$x=y-9...eqn3$

We put equation (3) into equation (1) to obtain,

$y=3(y-9)-1$

We expand the bracket to get,

$y=3y-27-1$

Group like terms to get,

$y-3y=-27-1$

We simplify to get;

$-2y=-28$

This implies that,

$y=14$

Therefore the y-coordinate is 14.

4 0

4 years ago

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