All categories

3 years ago

Check whether 7+3x is a factor of 3x^3+7x

Mathematics

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

Step-by-step explanation:

refer to picture for solution

You might be interested in

Which graph represents the solution to this inequality? 16x-80x<37+27

marin [14]

Answer:

Step-by-step explanation:

Hope this helps

8 0

2 years ago

Solve for x: |1/3-x/4|=7/12

ozzi

Your answer is x={-1, 11/3}

4 0

3 years ago

How do you write 283,980 in expanded form

kramer

Enjoy
200,000 + 80,000 + 3,000 + 900 + 80

6 0

3 years ago

Read 2 more answers

A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui

Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= $\frac{dx}{dt}=1. 8 m/s$

$\triangle ABD\sim\triangle ECD$

Therefore, $\frac{AB}{EC}=\frac{BD}{CD}$

$\frac{y}{2}=\frac{12}{x}$

$xy=24$

Differentiate w.r.t t

$x\frac{dy}{dt}+y\frac{dx}{dt}=0$

$x\frac{dy}{dt}=-y\frac{dx}{dt}$

$\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}$

When the man is 4 m from the building

Then, we have x=12-4=8 m

$\frac{dx}{dt}=1.8 m/s$

Substitute the values in above equation then, we get

$8y=24$

$y=\frac{24}{8}=3$

Substitute the values then we get

$\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s$

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0

3 years ago

Helppp mee asap !!!!!!

weqwewe [10]

Hyfgjgfthkok Hendrix djdhfnf fjfjfnfj fnnnnf fjjfjfnf fjfjfnfj

3 0

3 years ago