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Naily [24]
3 years ago
15

What is the value of y?

Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer:

The answer is C (46)

Step-by-step explanation:

Since the measurement of the triangle is 180 then you must subtract 180 by 88 to create 92 and divided that 92 by 2 to get 46.

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Select the correct answer.
V125BC [204]

Answer:

b

Step-by-step explanation:

any set times the radius will give you the answer

3 0
3 years ago
(x-1)(x+2)=5(x-1) divided by x-1
anyanavicka [17]
Assuming that your question is (x-1)(x+2) = [5(x-1)]/x-1

On the right side, the x-1's will cancel out, leaving you with (x-1)(x+2) = 5

expand the left side, giving you x^2 + x -2 = 5
which goes to x^2 +x -7 = 0
the possible values for x are 2.93 and -3.93. I don't think this was your question, so I'll do the other possible question that you might have been asking.

(x-1)(x+2) = 5(x-1)

divide by x-1 on both sides, leaving you with x+2=5
x+2=5
x=5-3
x=3
5 0
3 years ago
Martha spent $38.45 on a new shirt and now has $17.71 in her pocket.
Lelechka [254]

Answer:

x + 17.71= 38.45

Step-by-step explanation:

8 0
3 years ago
The third term in an arithmetic sequence is 10 and the fifth term is 26.If the first term is a1,which is an equation for the nth
dexar [7]
Just plug in 3 for n and then 5 for n to see if an turns out to be 10 and 26.

n=3:
A) an = 8*3+10 = 34
B) an = 8*3 - 14 = 10  OK
C) an = 16*3+10 = 58
D) an = 16*3 - 38 = 10 OK

n=5:
B) an = 8*5-14 = 26 OK
D) an = 16*5 - 38 = 42

So the answer is B
5 0
3 years ago
Suppose that an airline uses a seat width of 16.7 in. Assume men have hip breadths that are normally distributed with a mean of
murzikaleks [220]

Answer:

Step-by-step explanation:

Given that X, the hip width of men is N(14.2, 0.9)

i.e. we have \frac{x-14.2}{0.9} is N(0,1)

Seat width an airline uses = 16.7 inches.

a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in

=P(X>16.7 inches)\\= P(Z>\frac{16.7-14.2}{0.9} =P(Z>2.77)\\\\\\=P(Z>0)-(0

b) Here sample size = 126

Each person is independent of the other

the probability that these men have a mean hip breadth greater than 16.7

=0.0028^{126} <0.00001

c) part a is important since even a single person not fitting will cause embarassment and leads to customer dissatisfaction.

5 0
3 years ago
Read 2 more answers
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