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3 years ago

Which is not a cost for organisms that sexually reproduce?

Biology

1 answer:

Alekssandra [29.7K]3 years ago

3 0

Answer:

Identical shape and structure.

Explanation:

Those organisms that reproduce sexually have high variations and differences between the parent and its offspring. They are not identical to each other because the offspring gains half characteristics from male parent and half from the female parent making it different from its parent. Identical feature is present in the organisms that reproduce through asexually means from only one parent so the identical shape and structure is not the cost of sexual reproduction.

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Review -

Nina [5.8K]

Answer:

A. Survive environmental changes.

Explanation:

Genomics refers to the scientific study of genes (DNA) found in living organisms such as humans and animals.

A genome can be defined as the complete set of hereditary instructions that is typically found in the deoxyribonucleic acid (DNA).

Deoxyribonucleic acid (DNA) is an organic complex-molecular structure found in all living organisms. It comprises of genes and is essentially the foundation block of all living organisms.

Natural selection can be defined as a biological process in which species of living organisms having certain traits that enable them to adapt to environmental factors such as predators, competition for food, climate change, sex mates, etc., tend to survive and reproduce, as well as passing on their genes to subsequent generations.

Simply stated, natural selection entails the survival of the fittest. Therefore, the species that are able to adapt to the environment will increase in number while the ones who can't adapt will die and go into extinction.

The characteristics which are consistent with the concept of natural selection includes;

I. More offspring are produced than can survive in an environment (overproduction of offspring). This ultimately implies that, the more offsprings that are reproduced by the parent organism, the more likely are they to survive.

II. There is genetic variation within populations. This simply means that there is a better chance of having good or beneficial traits being passed from the parent organism to her offsprings.

III. Organisms with beneficial variations are more likely to survive and reproduce, as well as passing on their genes to subsequent generations.

Hence, a population of living organisms with a large gene pool (gene diversification) is more favorably disposed to survive environmental changes than a species population having a small gene pool.

In conclusion, the higher the genetic makeup of a living organism, the higher are its chances of surviving environmental changes in the ecosystem.

7 0

3 years ago

Someone help me please I’ll make brainlist!! Quick fast

yulyashka [42]

Answer:

I think this is 2 because there would have been bigger predators in the ocean vs. a lake

4 0

3 years ago

4) A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality)

docker41 [41]

Answer and Explanation:

A homozygous groucho fly ( gro, bristles clumped above the eyes) is crossed with a homozygous rough fly (ro, eye abnormality).

The F1 females are testcrossed, producing these offspring: groucho 518 rough 471 groucho, rough 6 wild-type 5 1000 a) What is the linkage distance between the two genes? B) Plot the genes on a map c) If the genes were unlinked and the F1 females were mated with the F1 males, what would be the offspring in the F2 generation?

1st cross:

Parental) grogro ro+ro+ x gro+gro+ roro

F1) gro+gro ro+ro

2nd cross:

Parental) gro+gro ro+ro x grogro roro

Gametes) gro+ro+ gro ro

gro+ro gro ro

gro ro+ gro ro

gro ro gro ro

Punnet square)

gro+ro+ gro+ro gro ro+ gro ro

gro ro gro+gro ro+ro gro+gro roro grogro ro+ro grogro roro

F2)

0.518 grogro ro+ro (518 individuals)

0.471 gro+gro roro (471 individuals)

0.006 grogro roro (6 individuals)

0.005 gro+gro ro+ro (5 individuals)

Total number of individuals 1000

Note: These frequencies were calculated dividing the number of individuals belonging to each genotype by the total number of individuals in the F2.

To know if two genes are linked, we must observe the progeny distribution. If individuals, whos genes assort independently, are test crossed, they produce a progeny with equal phenotypic frequencies 1:1:1:1. If we observe a different distribution, that is that phenotypes appear in different proportions, we can assume that genes are linked in the double heterozygote parent.

In the exposed example we might verify which are the recombinant gametes produced by the F1 di-hybrid, and we can recognize them by looking at the phenotypes with lower frequencies in the progeny.

By performing this cross we know that the phenotypes with lower frequencies in the progeny are groucho, rough and wild-type. So the recombinant gametes are gro+ro+ and gro ro, while the parental gametes are gro+ro and gro ro+.

So, the genotype, in linked gene format, of the double heterozygote individual in the F1 is gro+ro/gro ro+.

To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals. The genetic distance will result from multiplying that frequency by 100 and expressing it in map units (MU). One centiMorgan (cM) equals one map unit (MU).

The map unit is the distance between the pair of genes for which one of every 100 meiotic products results in a recombinant product.

The recombination frequency is:

P = Recombinant number / Total of individuals

P = 6 + 5 / 1000

P = 11 / 1000

P = 0.011

The genetic distance between genes, is 0.011 x 100= 1.1 MU.

Genetic Linkage Map:

Parental Phenotypes)

-----gro+------ro---- -----gro------ro+----

----- gro ------ro---- ---- gro------ ro ----

Recombinant phenotypes)

-----gro+------ro+---- -----gro------ro----

----- gro ------ ro---- -----gro------ro----

If the genes were unlinked and the F1 females were mated with the F1 males, the offspring in the F2 generation would have been

4/16 = 1/4 gro+gro ro+ro

4/16 = 1/4 gro+gro roro

4/16 = 1/4 grogro ro+ro

4/16 = 1/4 grogro roro

Their phenotypic frequencies would be 1:1:1:1 related.

7 0

3 years ago

Which cross could produce a child with blood type A?

Strike441 [17]

Answer:

d. Ao x oo

Explanation:

The other crosses with A would all result in complete dominance because the alleles (other than A) from the other parent are dominant. Because option D. crosses a h o m o zygous parent with a recessive trait, the cross could produce a child with blood type A.

8 0

3 years ago

Read 2 more answers

If you graduate student is studying the influence of biology on behavior and mental processes what field of psychology would the

maria [59]

Behavioral Psychology

3 0

3 years ago