Answer:
76%
Step-by-step explanation:
Times the decimal by 100 to get a percent
basically moving the decimal 2 spaces to the right.
Answer:
3 times
Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3
This means that the large diameter is 3 times the small one.
Hope this helps :)
Since you know it's a square, you also know that all the sides are 3 2/3. So to find area you multiply, so 3 2/3 x 3 2/3. An easy way to do this is convert it to a mixed number (11/3) and then multiply:
11/3 x 11/3 = 121/9
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
