Plug in x = 12 and y = -5 into the given equation:-
3(12) - 3(-5) = 36 + 15 = 51 Not 21
So (12,-5) is not a solution.
Answer:
y = (2/3)x - 3
Step-by-step explanation:
Slope-intercept form: y = mx + b
Note that:
y = (x , y)
m = slope
x = (x , y)
b = y-intercept.
The point is given to you. Note that:
(x , y) = (0 , -3) ∴
x = 0
y = -3
The slope = m = 2/3
Plug in the corresponding numbers to the corresponding variable:
y = mx + b
-3 = (2/3)(0) + b
-3 = 0 + b
b = -3
Plug in -3 for b in the equation:
y = mx + b
y = (2/3)x -3
y = (2/3)x - 3 is your equation.
~
I assume you mean one that is not rational, such as √2. In such a case, you make a reasonable estimate of it's position, and then label the point that you plot.
For example, you know that √2 is greater than 1 and less than 2, so put the point at about 1½ (actual value is about 1.4142).
For √3, you know the answer is still less than 4, but greater than √2. If both of those points are required to be plotted just make sure you put it in proper relation, otherwise about 1¾ is plenty good (actual value is about 1.7321).
If you are going to get into larger numbers, it's not a bad idea to just learn a few roots. Certainly 2, 3, and 5 (2.2361) and 10 (3.1623) shouldn't be too hard.
Then for a number like 20, which you can quickly workout is √4•√5 or 2√5, you could easily guess about 4½ (4.4721).
They're usually not really interested in your graphing skills on this sort of exercise. They just want you to demonstrate that you have a grasp of the magnitude of irrational numbers.
Answer:
-4
Step-by-step explanation:
-*- =+
Answer:
x=3
y=3
Step-by-step explanation:
x = 6-y
-plug in (6-y) into first equation
2(6-y)+3y = 15
12-2y+3y=15
-2y+3y = 3
y=3
x=6-3
x=3
double check:
(2*3) + (3*3) = 6 + 9 = 15
3 + 3 = 6
