Please help I will give brainliest

A roulette wheel has 38 pockets numbered 0,00,and 1 to 36. Of all 38 pockets 18 are red, 18 are black and 2 are green. Each time

Fiesta28 [93]

Answer:

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

Step-by-step explanation:

Each spin is independent of the others, so the probabilities of the three possible outcomes (R,G,B) for each spin are:

P(R) = (18/38)

P(G) = (2/38)

P(B) = (18/38)

4 0

2 years ago

I don't get how to do this, can someone help?

Marianna [84]

Google helps to so try that

4 0

3 years ago

Math problem: electrical polls that carry electrical wire seem.to get smaller the farther away they are from you. find the appar

vivado [14]

Mayonnaise is an instrument

7 0

2 years ago

9a - 3 (a - 6) = -6 a=___

leonid [27]

9a - 3(a - 6) = -6...distribute thru the parenthesis
9a - 3a + 18 = -6....subtract 18 from both sides
9a - 3a = -6 - 18 ...combine like terms
6a = - 24...divide both sides by 6
a = -24/6
a = - 4

7 0

2 years ago

. At a clothing store, 12 people purchased blue sweaters, 8 purchased green sweaters, 4 purchased gray sweaters, and 7 purchased

DedPeter [7]

Answer:

The probability that they purchased a green or a gray sweater is $\frac{12}{31}$

Step-by-step explanation:

Probability is the greater or lesser possibility of a certain event occurring. In other words, probability establishes a relationship between the number of favorable events and the total number of possible events. Then, the probability of any event A is defined as the quotient between the number of favorable cases (number of cases in which event A may or may not occur) and the total number of possible cases. This is called Laplace's Law.

$P(A)=\frac{number of favorable cases}{number of possible cases}$

The addition rule is used when you want to know the probability that 2 or more events will occur. The addition rule or addition rule states that if we have an event A and an event B, the probability of event A or event B occurring is calculated as follows:

P(A∪B)= P(A) + P(B) - P(A∩B)

Where:

P (A): probability of event A occurring.

P (B): probability that event B occurs.

P (A⋃B): probability that event A or event B occurs.

P (A⋂B): probability of event A and event B occurring at the same time.

Mutually exclusive events are things that cannot happen at the same time. Then P (A⋂B) = 0. So, P(A∪B)= P(A) + P(B)

In this case, being:

P(A)= the probability that they purchased a green sweater
P(B)= the probability that they purchased a gray sweater
Mutually exclusive events

You know:

8 purchased green sweaters
4 purchased gray sweaters
number of possible cases= 12 + 8 + 4+ 7= 21

So:

$P(A)=\frac{8}{31}$

$P(B)=\frac{4}{31}$

P(A⋂B) = 0

Then:

P(A∪B)= P(A) + P(B)

P(A∪B)= $\frac{8}{31}+ \frac{4}{31}$

P(A∪B)= $\frac{12}{31}$

The probability that they purchased a green or a gray sweater is $\frac{12}{31}$

5 0

2 years ago