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3 years ago

Can someone plz help me with this one problem!!

Mathematics

2 answers:

Yuri [45]3 years ago

7 0

Uhhh the answer is no

NNADVOKAT [17]3 years ago

3 0

Answer:

Step-by-step explanation:

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Q6) Renee buys 5kg of sweets to sell. She pays £10 for the sweets. Renee puts all the sweets into bags. She puts 250g of sweets

My name is Ann [436]

Answer:

30% percent profit

Step-by-step explanation:

100 pence in a pound.

1000 grams in a kilogram.

She bought 5000g of sweets.

She pays 10×100=1000 pence.

She put them into 5000÷250=20 bags.

She sells the bags for 65 pence each.

She sells them all for 20×65=1300 pence.

She gets a profit of 300 pence or 3 pounds.

She gets a percent profit of 30%.

3 0

3 years ago

If 2x = 3y + 11 and 2 to the power of x = 2 to the power of 4(y+1), determine the value of x + y

evablogger [386]

Z = -2

Y = 5

is your answer

7 0

3 years ago

Ranger says the expression is not in its simplest form. He thinks the two terms need to be combined. Is Ranger right that 8x − 2

ladessa [460]

Answer:

4(2x - 5)

Step-by-step explanation:

Rewrite "20" as 4 * 5

Rewrite "8" as 4 * 2

=4 * 2x - 4 * 5

Factor out common term "4"

=4(2x - 5) <------ Your answer.

5 0

3 years ago

Read 2 more answers

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :