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Zielflug [23.3K]
3 years ago
14

Can someone plz help me with this one problem!!

Mathematics
2 answers:
Yuri [45]3 years ago
7 0
Uhhh the answer is no
NNADVOKAT [17]3 years ago
3 0

Answer:

No

Step-by-step explanation:

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ANSWER ASAP I WILL GIVE BRAINLIST
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its upside down

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The length of a rectangle is four time its width. If the permeter of the rectangle is 100yd, find i t s length and width.​
seropon [69]

Answer:

So let us call the shorter side, i.e the width: 'x'

So each length is four times the width = 4x

The perimeter consists of two widths and two lengths and equals 50 inches.

So:

x+x+4x+4x=50

solve for x:

10x = 50

to find x divide both sides by 10:

10x/10 = 50/10

x=5

So width equals 5 in and length is four times this i.e. 4x5=20

To check: 5+5+20+20=50 !!!!

Step-by-step explanation:

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3 years ago
On a coordinate plane, point C has coordinates of (-8, -15) and point D has coordinates of (9, -3). What are the coordinates of
Anna [14]

Answer: H

Step-by-step explanation:

4 0
3 years ago
Can you solve R=4+7x-sx
ivanzaharov [21]
<span>R = 4 + -1sx + 7x here</span>
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4 years ago
Guys help i don't know this please be quick
andrew11 [14]

Hello damerahli!

\huge \boxed{\mathfrak{Question} \downarrow}

Find the landmark.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

Let's take a look at the graph. The coordinates given are (2, ¼).

This means that...

  • Coordinate at abscissa = 2
  • Coordinate at ordinate = ¼

In the graph given, each square = ¼ units. That means the 1st box above the origin in the ordinate is (0, ¼). Let's mark this as our coordinate of y-axis. Then let's take 2 in the abscissa (2, 0) as the other coordinate. So, by connecting the 2 points (since both the coordinates are positive they'll lie in the 1st quadrant) we can see that the landmark is the \boxed{\underline{\bf \: FBI\: Building}}. (Marked as a yellow dot in the attached figure).

<em>Please </em><em>refer </em><em>to </em><em>the attached</em><em> picture</em><em> for</em><em> better</em><em> understanding</em><em>.</em>

__________________

Hope it'll help you!

ℓu¢αzz ッ

7 0
3 years ago
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