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Aleks [24]
3 years ago
15

The movie theater sells adult tickets for $10 and kids

Mathematics
1 answer:
Maurinko [17]3 years ago
4 0

Answer:

On Tuesday 8 adult tickets and 12 child tickets were sold.

Step-by-step explanation:

Since the movie theater sells adult tickets for $ 10 and kids tickets for $ 8, and they sold $ 176 worth of tickets last Tuesday with a total of 20 ticket sales, to determine how many tickets of each type were sold, the following calculation must be performed:

10 - 8 = 2

20 x 8 = 160

176 - 160 = 16

16/2 = 8

8 x 10 + 12 x 8 = X

80 + 96 = X

176 = X

Therefore, on Tuesday 8 adult tickets and 12 child tickets were sold.

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At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Ge
balandron [24]

Answer:

Each student ticket costs $8.33

Each adult ticket costs $15.34

Step-by-step explanation:

At Niagra High, Mr. Borton bought 4 student tickets and 2 adult tickets for the high school musical which cost $64. then Mrs. Gelvoria bought 3 student tickets and 3 adult tickets for the show and it cost her $72. How much are each type of tickets?​

s = cost of each student ticket

a = cost of adult ticket

Our system of equations:

4s + 2a = 64

3s + 3a = 71

-3(4s + 2a = 64) ==> -12s - 6a = -192

2(3s + 3a = 71) ==>     6s + 6a = 142

-12s - 6a = -192

  6s + 6a = 142

-6s = -50

/-6      /-6

s = $8.33 (the cost of each student ticket)

Now, let's find the cost of each adult ticket:

4s + 2a = 64

4(8.33) + 2a = 64

33.32 + 2a = 64

-33.32         -33.32

2a = 30.68

/2        /2

a = 15.34 (the cost of each adult ticket)

(x, y) ==> (8.33, 15.34)

Check your answer:

4s + 2a = 64

4(8.33) + 2(15.34) = 64

33.32 + 30.68 = 64

64 = 64

This statement is true

Hope this helps!

8 0
3 years ago
Who's is the faster runner? Raj can run 1 1/3 laps in 1/4 of an hour. Yvonne can run 4 1/2 laps in 7/8 of an hour.
SpyIntel [72]
Raj can run faster than yvonne
4 0
3 years ago
Read 2 more answers
A box of Georgia peaches has 3 bad and 12 good peaches. (a) If you make a peach cobbler of 12 peaches randomly selected from the
Eddi Din [679]

Answer:

a) 0.21% probability that there are no bad peaches in the peach cobbler.

b) 99.79% probability of having at least 1 bad peach in the peach cobbler

c) 7.91% probability of having exactly 2 bad peaches in the peach cobbler.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the peaches are chosen is not important. So the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

(a) If you make a peach cobbler of 12 peaches randomly selected from the box, what is the probability that there are no bad peaches in the peach cobbler?

Desired outcomes:

12 good peaches, from a set of 12. So

D = C_{12,12} = \frac{12!}{12!(12 - 12)!} = 1

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{1}{455} = 0.0021

0.21% probability that there are no bad peaches in the peach cobbler.

(b) What is the probability of having at least 1 bad peach in the peach cobbler?

Either there are no bad peaches, or these is at least 1. The sum of the probabilities of these events is 100%. So

p + 0.21 = 100

p = 99.79

99.79% probability of having at least 1 bad peach in the peach cobbler

(c) What is the probability of having exactly 2 bad peaches in the peach cob- bler?

Desired outcomes:

2 bad peaches, from a set of 3.

One good peach, from a set of 12.

D = C_{3,2}*C_{12,1} = \frac{3!}{2!(3-2)!}*\frac{12!}{1!(12 - 1)!} = 36

Total outcomes:

12 peaches, from a set of 15. So

T = C_{15,12} = \frac{15!}{12!(15 - 12)!} = 455

Probability:

p = \frac{D}{T} = \frac{36}{455} = 0.0791

7.91% probability of having exactly 2 bad peaches in the peach cobbler.

3 0
3 years ago
Dan was thinking of a number. Dan doubles it and gets an answer of 34.7. What was the original number?
Ksju [112]
347/2 just did it!!! Good luck
3 0
3 years ago
Read 2 more answers
If a/b and c/d are rational expressions then a/b divided by c/d =a times d/b times c true or false
Tomtit [17]

Answer:

(a d)/(bc)

Step-by-step explanation:

a/b ÷ c/d

Copy dot flip

a/b * d/c

ad / bc

4 0
3 years ago
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