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Nutka1998 [239]
3 years ago
11

What is the surface area of this rectangular pyramid?

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

304m^2

Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

(12m) (8m)= 96m^2

Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

1/2 (12m) (10m)= 60m^2

Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

SA=  (96m^2) +(120m^2) +(88m^2)

SA= 304m^2

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Answer:

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Step-by-step explanation:

8^-1 * 3^3/ 2^-4 * 9^-2

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2^4 * 3^3 * 3^4 / 2^3

2^4/ 2^3 = 2   and 3^3 * 3^4 = 3^(3+4) = 3^7

2* 3^7

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3 years ago
Solve x 2 - 4x - 7 = 0 by completing the square. What are the solutions?
Bingel [31]

Answer:

x = 2±sqrt(11)

Step-by-step explanation:

x^2 -4x - 7 =0

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x^2 -4x -7+7 =0+7

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To complete the square take the coefficient of the x term and  divide by 2 and then square it.  Add it to both sides

-4 /2 = -2 then square

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Add 4 to both sides

x^2 -4x+4 =7+4

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Factor the left side into (x-b/2)^2

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3 years ago
Which statement is true?
defon

Answer:

b. Multiplying decimals less than one is finding a part of a part.

Step-by-step explanation:

A part of a given number implies a selected part of a given number which can be expressed as a fraction of the number. Example, the half of any number is \frac{1}{2}.

The product of a part and another part can be expressed as;

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or,

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The three examples shows: a part x a part.

Therefore, it would be observed that multiplying decimals less than one is the same as finding a part of a part.

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