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Nutka1998 [239]
3 years ago
11

What is the surface area of this rectangular pyramid?

Mathematics
1 answer:
Alexxx [7]3 years ago
7 0

Answer:

304m^2

Step-by-step explanation:

First find the surface area of the base by multiplying the length by the width.

(12m) (8m)= 96m^2

Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.

1/2 (12m) (10m)= 60m^2

Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.

1/2 (8m) (11m)= 44m^2

Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.

base=a, front/ back triangles= b, side triangles=c

SA= a + 2b +2c  or SA= a +b +b +c +c

Using one of the equations above solve for the total surface area.

SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)

or

SA= (96m^2) + 2(60m^2) +2(44m^2)

SA=  (96m^2) +(120m^2) +(88m^2)

SA= 304m^2

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Answer:

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Step-by-step explanation:

The formula for finding the volume of a spherical object is 4/3(π)(r^3),where r is the radius of the object. But here only the diameter was given. And diameter=2(r), where r is radius.

So to find the radius, divide the diameter by 2. Since by making r the subject of the equation you get r=diameter/2.

Using the formula

4/3(π)(r^3)=(4π((15/2)^3))/3

=(4π(7.5^3)/3

=(4π(421.875))/3

Since π is 3.141592654

(4π(421.875))/3=1/3(4(3.141592654)(421.875))

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Answer:

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<em>In 2001, 63%</em>

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<em>In 2003, 61%</em>

<em>In 2004, 60%</em>

<em>And so on</em>

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To go to 30% from 60% in 2004, we would need to decrease 60 - 30 = 30%, and that will occur after 30 more years. So that would be the year

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lutik1710 [3]

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Specifically it is a 0.9% decrease since 0.009 = 0.9/100 = 0.9%

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Step-by-step explanation:

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3 years ago
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mezya [45]

Answer:

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