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Shalnov [3]
3 years ago
9

ABC are points; (2,3), (4,7), (7,3) respectively. Find the equation of the line through the point (3,-5) which is parallel to th

e line with the equation 3x+2y-5=0​
Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

y = -3x/2 - 1/2

Step-by-step explanation:

slope m = -3/2

-5 = (-3/2)×3+b

or, b = -1/2

putting it into y = mx + b

y = -3x/2 - 1/2

Answered by GAUTHMATH

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What time is 7 1/2 hours before 2:12
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6:42 pm bc subtract 2 hours is 12:12am and then subtract the rest is 7:12pm then you subract 12 minutes is 7 pm the subtract the 18 minutes left is 6:42 pm
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3 years ago
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The area of a triangle is 36 4/5 units squared and the height of the triangle 9 1/5 what is the length of the triangles base
den301095 [7]

Answer:

Height = 8 units

Step-by-step explanation:

Area of a triangle = 36\frac{4}{5} square units

                             = \frac{184}{5} square units

Height of the triangle = 9\frac{1}{5} units

                                    = \frac{46}{5} units

Formula to calculate the area of a triangle is,

Area = \frac{1}{2}(\text{Base})(\text{Height})

\frac{184}{5}= \frac{1}{2}\times (\frac{46}{5})\times (\text{Height})

\frac{184}{5}= (\frac{46}{10})\times (\text{Height})

Height = \frac{184}{5}\times \frac{10}{46}

           = \frac{368}{46}

           = 8 units

Therefore, height of the given triangle is 8 units.

6 0
2 years ago
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Maria can read 20 pages of economics in an hour. She can also read 50 pages of sociology in a hour. She...? Maria can read 20 pa
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B.) Marua will spend 2 hours to read 100 pages of sociology which means she can only read 60 pages of economics.
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8 0
3 years ago
Solve the equation 2(3x + 7) + 5 = 49.
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Answer:

x=5

Step-by-step explanation:

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2 years ago
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Write a quadratic function to model the vertical motion for each​ situation, given ​h(t) equals negative 16t squared plus v0t+h0
Mashcka [7]

Answer:

hmax = 194 ft

The maximum height is 194 ft

Step-by-step explanation:

According to the given equation for the model of the vertical motion. The height at any point in time can be written as;

h(t) = -16t^2 + v0t + h0 .......1

Where;

h(t) = height at time t

t = time

v0 = initial velocity = 96 ft/s

h0 = initial height = 50 ft

To determine the maximum height we need to differentiate the equation 1 to find the time at which it reaches maximum height;

At the highest point/height h' = dh/dt = 0

h'(t) = -32t +v0 = 0

-32t + v0 = 0

t = v0/32

t = 96/32

t = 3 s

At t=3 it is at maximum height.

The maximum height can be derived from equation 1;

Substituting the values of t,v0,h0 into equation 1;

h(t) = -16t^2 + v0t + h0 .......1

hmax = -16(3)^2 + 96(3) + 50 = 194 ft

hmax = 194 ft

The maximum height is 194 ft

5 0
3 years ago
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