Determine and state an equation of the line perpendicular to the line 8x + 6y = 15 and passing through the point (3,-4)
1 answer:
Answer:
4y - 3x = -25
Step-by-step explanation:
The equation of a line in point-slope form is expressed as
y - y0 = m(x - x0)
(x0, y0) is the point
m is the slope
Given
(x0, y0) = (3, -4)
Also given the equation;
8x + 6y = 15
Rewrite in standard form;
6y = -8x+15
y = -8/6 x + 15/6
y = -4/3 x + 5/2
Slope m = -4/3
Since the required line is perpendicular to the given line =,
Slope = -1/(-4/3) = 3/4
Substitute into the formula;
y - (-4) = 3/4(x-3)
y + 4 = 3/4(x-3)
4(y+4) = 3(x-3)
4y + 16 = 3x - 9
4y - 3x = -9-16
4y - 3x = -25
This gives the required equation
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