If you factored this the outcome would be,
(q+3)(3p^2-4)
Area of <span>parallelogram=base * height
so it is 12*9=108 yd²</span>
Answer:
-10<0
Step-by-step explanation:
Factor out the trinomial. Find factors of x² and 6 that would, when added, give you 5x
x² = x * x
6 = 3 * 2
(x + 3)(x + 2) are your binomials.
To solve for x, set each parenthesis = 0
x + 3 = 0
x + 3 (-3) = 0 (-3)
x = -3
x + 2 = 0
x + 2 (-2) = 0 (-2)
x = -2
x = -3, -2
hope this helps
Answer:
H0: μd=0 Ha: μd≠0
t= 0.07607
On the basis of this we conclude that the mean weight differs between the two balances.
Step-by-step explanation:
The null and alternative hypotheses as
H0: μd=0 Ha: μd≠0
Significance level is set at ∝= 0.05
The critical region is t ( base alpha by 2 with df=5) ≥ ± 2.571
The test statistic under H0 is
t = d/ sd/ √n
Which has t distribution with n-1 degrees of freedom
Specimen A B d = a - b d²
1 13.76 13.74 0.02 0.004
2 12.47 12.45 0.02 0.004
3 10.09 10.08 0.01 0.001
4 8.91 8.92 -0.01 0.001
5 13.57 13.54 0.03 0.009
<u>6 12.74 12.75 -0.01 0.001</u>
<u>∑ 0.06 0.0173</u>
d`= ∑d/n= 0.006/6= 0.001
sd²= 1/6( 0.0173- 0.006²/6) = 1/6 ( 0.017294) = 0.002882
sd= 0.05368
t= 0.001/ 0.05368/ √6
t= 0.18629/2.449
t= 0.07607
Since the calculated value of t= 0.07607 does not falls in the rejection region we therefore accept the null hypothesis at 5 % significance level . On the basis of this we conclude that the mean weight differs between the two balances.
