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3 years ago

Need a correct answer please

Mathematics

2 answers:

zepelin [54]3 years ago

8 0

What’s the question

nydimaria [60]3 years ago

8 0

Answer:

$239.02 and $10177

Step-by-step explanation:

Ann:

2868.32/6= 478.05

478.05/2= 239.02

Ann's sister:

3562.28/7= 508.89

508.89/5= 101.77

dont know if i did this right to be completely honest. but i feel like it's right. sorry if it's not.

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1 6 4n+ 35 +6q+ + 3n - 4q=1 35 10 Points

sergey [27]

Answer:

7n + 1/5 + 2q

Step-by-step explanation:

Identify like terms

(4n + 3n) + (6/35 + 1/35) + (6q -4q)

Add like terms

7n + 7/35 + 2q

7/35 simplifies to 1/5

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3 years ago

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3 years ago

What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where

Setler79 [48]

Answer:

$k=-16,k=-8,k=8,k=16$

Step-by-step explanation:

We are given quadratic equations as

$x^2+kx+15$

and it can be factored as

$=(x+a)(x+b)$

now, we can multiply factor term

$(x+a)(x+b)=x^2+(a+b)x+ab$

now, we can compare

$x^2+(a+b)x+ab=x^2+kx+15$

so, we get

$k=a+b$

$ab=15$

we are given that

'a' and 'b' are integers

so, we can find all possible factors

$15=(-1\times -15),(1\times 15)$

$15=(-3\times -5),(3\times 5)$

so, we can find k

At $(-1\times -15)$ :

$k=a+b$

we can plug values

$k=-1-15$

$k=-16$

At $(1\times 15)$ :

$k=a+b$

we can plug values

$k=1+15$

$k=16$

At $(-3\times -5)$ :

$k=a+b$

we can plug values

$k=-3-5$

$k=-8$

At $(3\times 5)$ :

$k=a+b$

we can plug values

$k=3+5$

$k=8$

So, values of k are

$k=-16,k=-8,k=8,k=16$

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Answer:

315 sq. in

Step-by-step explanation:

15 * 21 = 315

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