All you do is have to plug each option in for x
2*18^2=684
2*36^2=2592
2*6^2=72
2*8^2=128
So it's C.6
1 3/7 ~ One and three sevenths
Answer:
p(s) = 0,33
Step-by-step explanation:
n = 450
p₀ = 150/450 p₀ = 0,33 then q₀ = 0,67
n*p₀ = 0,33*450 = 150
n*q₀ = 0,67*450 = 301
n*p₀ and n*q₀ more than 10, we can approximate the binomial to a Normal Distribution Distribution
a) p - p₀ = z(c) * √ (p₀q₀)/n
z(c) = ??
CI 95 % then α = 5 % α = 0,05 α/2 = 0,025
z(c) = 1,96
p = p₀ ± z(c) * √ (p₀q₀)/n
p = 0,33 ± 1,96 * 0,022
p = ( 0,33 - 0,04 ; 0,33 + 0,04
p = ( 0,29 ; 0,37 )
The value of the center of the confidence Interval is 0,33
p(s) = 0,33
(y-3)^2 -4y +12 = 0
[y^2 -6y +9] -4y +12 =0
y^2 -10y + 21 = 0
(y -3) (y-7) =0
y=3 ; y = 7
Answer:
If I ran 3/4 of an 8 mile run, how much did I run?
3/4*8= 6 miles
Step-by-step explanation:
Mark Brainliest please
