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bonufazy [111]
3 years ago
8

Back to the cute little pigs. What are the possible parents of the following groups of guinea pigs. Give all possibilities. You

do not need to show Punnett Squares, just the possible parents. There may be more than I answer for each. Case 1: 50 % of the offspring are black Case 2: 75 % of the offspring are black Case 3: 50 % of the offspring are hybrid black Case 4: 100 % of the offspring are black Case 5: 100 % of the offspring are white Case 6: 50 % of the offspring are white Case 7: 25 % of the offspring are white​
Biology
1 answer:
frez [133]3 years ago
6 0

Answer:

Case 1 ⇒ Bb   x   bb ⇒ F1 = 50% Bb, black + 50% bb, white

Case 2 ⇒ Bb   x   Bb ⇒ F1 = 75% Black + 25% white

Case 3 ⇒ Bb   x   Bb ⇒ F1 = 25% BB + 50% Bb + 25% bb

            ⇒ Bb   x   bb ⇒ F1 = 50% Bb + 50% bb

Case 4 ⇒  BB   x   BB ⇒ F1 = 100% BB Black

            ⇒ Bb   x   BB ⇒ F1 = 50% BB + 50% Bb = 100% Black

            ⇒ bb   x   BB ⇒ F1 = 100% Bb black

Case 5 ⇒ bb   x   bb ⇒  F1 = 100% bb white

Case 6 ⇒ Bb   x   bb ⇒ F1 = 50% Bb black + 50% bb white

Case 7 ⇒ Bb  x  Bb ⇒ F1 = 75% black + 25% white

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

Download pdf
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Answer:

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There are certain limitations associated with the Punnett Squares. They are not useful in case of complex genetic inheritance such as linkage between two genes. In case of linkages it becomes difficult to estimate the distribution of genotypes and phenotypes. For example in case of  Nail-patella Syndrome and gene associated with blood group two genes lie on the same chromosome in close vicinity and hence there are high chances of inheritance of these traits in the offspring from the parent thereby causing  random distribution of the two traits. This random distribution cannot be captured through punnet square.  

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