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The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
Given
On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80).
<h3>Coordinates</h3>
The coordinates point any point can be found by using the following formula.

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is;

Hence, the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
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Answer:
19 + 14 + 10 = 43
Step-by-step explanation:
Answer: 
Step-by-step explanation:
1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.
2. The equation given in the problem is written in Point-slope form:

Where m is the slope.
3. Therefore, the slope of its perpendicular line must be:

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

5. In slope intercept form is:
