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d1i1m1o1n [39]
3 years ago
6

Nancy is checking to determine if the expressions x + 4 + x and 6 + 2 x minus 2 are equivalent. When x = 3, she correctly finds

that both expressions have a value of 10. When x = 5, she correctly evaluates the first expression to find that x + 4 + x =14. What is the value of the second expression when x = 5, and are the two expressions equivalent? The value of the second expression is 8, so the expressions are not equivalent. The value of the second expression is 14, so the expressions are equivalent. The value of the second expression is 16, so the expressions are equivalent. The value of the second expression is 18, so the expressions are not equivalent.
Mathematics
2 answers:
Basile [38]3 years ago
8 0

Answer:

I believe is The value of the second expression is 14, so the expressions are equivalent.

Step-by-step explanation:

I took the test and got it right.

anastassius [24]3 years ago
3 0

Answer:

The value of the 2nd expression is 14, so the expressions are equivalent.

Step-by-step explanation:

6 + 2x - 2

6 + 2(5) - 2

6 + (10) - 2

16 - 2

14

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Helppp i need answer now will give points
Papessa [141]

Answer:

f(g(3)) = 3

Step-by-step explanation:

We are told to solve for f(g(3)). This is also saying f of g of 3.

To find f(g(3)), we need to plug 3 in for x in g(x), since it says g(3).

g(x) = 3(3) - 4

Solve.

= 9 - 4

g(x) = 5

Now, we plug that into f(x), because g(x) was placed inside f and replaces the x variable of f(x).

f(5) = 2(5) - 7

Solve.

= 10 - 7

f(5) = 3.

f(g(3)) = 3

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4 0
3 years ago
Please help me.<br> If △NMK ≅ △TRP, then answer the following questions:
Natalka [10]

Answer:

Answers are below.

Step-by-step explanation:

a. △MNK ≅ △RTP

b. TR ≅ NM

c. x = 7

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3 0
2 years ago
Find the length of rhombus whose diogonals are length 12 cm and 16 cm​
grin007 [14]

In ΔAOD  (AD)  =(AO)

2+(OD)

2   =36+64    AD

2 =100

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7 0
3 years ago
You run one lap around a mile track every 8 minuets. Your friend runs around the same track every 10 minutes. You both start at
GalinKa [24]
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3 years ago
Jimmy set his score for his math test. After the math teacher returnee his paper to him, he realized that if he increased his ta
mixer [17]
When ever you have percentages, it should be helpful to bear in mind you can express them as multipliers. In this case, it will be helpful.
So, if we let:
a = test score
b = target score
then, using the information given:
a = 1.1b + 1
a = 1.15b - 3
and we get simultaneous equations.
'1.1' and '1.15' are the multipliers that I got using the percentages. Multiplying a value by 1.1 is the equivalent of increasing the value by 10%. If you multiplied it by 0.1 (which is the same as dividing by 10), you would get just 10% of the value.
Back to the simultaneous equations, we can just solve them now:
There are a number of ways to do this but I will use my preferred method:
Rearrange to express in terms of b:
a = 1.1b + 1
then b = (a - 1)/1.1
a = 1.15b - 3
then b = (a + 3)/1.15
Since they are both equal to b, they are of the same value so we can set them equal to each other and solve for a:
(a - 1)/1.1 = (a + 3)/1.15
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0.05a = 4.45
a = 89

8 0
3 years ago
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