Let the two integers be x and x + 1, then
2(x + 1) + 9 = 3x
2x + 2 + 9 = 3x
3x - 2x = 11
x = 11
Therefore, the integers are 11 and 12.
We have that
the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]
if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17
<span>let's check it
</span>[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok
This will be an obtuse angled triangle because one angle is greater than 90 degrees.
The last side would be 10
Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4
