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chubhunter [2.5K]
3 years ago
11

Explain why any of the four operations placed between two terms 5 and -3 sqrt (8) will result in an irrational number

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0

Sum/difference:

Let

x = 5 + (-3\sqrt{8}) = 5-3\sqrt{8}

This means that

3\sqrt{8} = 5-x \iff \sqrt{8} = \dfrac{5-x}{3}

Now, assume that x is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that x was rational, which proves that the sum/difference of the two given terms was irrational

Multiplication/division:

The logic is actually the same: if we multiply the two terms we get

x = -15\sqrt{8}

if again we assume x to be rational, we have

\sqrt{8} = -\dfrac{x}{15}

But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.

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If 15% of 200 apples are bad, how many apples are bad?
jarptica [38.1K]
<h3><u>given</u><u>:</u></h3>

apples= 200

bad apples= 15%

<h3><u>to</u><u> </u><u>find</u><u>:</u></h3>

how many apples are bad.

<h3><u>solution</u><u>:</u></h3>

<u>200 \times  \frac{15}{100}</u>

<u>= 30</u>

<u>therefore</u><u>,</u><u> </u><u>there</u><u> </u><u>are</u><u> </u><u>3</u><u>0</u><u> </u><u>bad</u><u> </u><u>apples</u><u>.</u>

5 0
2 years ago
How do I solve “1+2+3+4+5+…100=“<br> A. 1010<br> B. 5050<br> C. 5000<br> D. 1000
irina [24]

Answer:

5050

Step-by-step explanation:

we know that 100/2 is 50 and 50 x 100 is 5000

so now another 50 is remaining but we can't multiply but add so

1+2+3+4+5...100 = in simple form= 50x100+50=5050//

5 0
2 years ago
given the function f(x) = 2^x, find the value of f−1(32). (1 point) f−1(32) = 0 f−1(32) = 1 f−1(32) = 5 f−1(32) = 16
EastWind [94]

Answer:

5

Step-by-step explanation:

The inverse of f(x)=2^x is g(x)=\log_2(x).

g(32)=\log_2(32)

\log_2(32)=5 since 2^5=32.

g(32)=\log_2(32)=5

Note: In general, the inverse of f(x)=a^x is g(x)=\log_a(x).

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3 years ago
Factor completely 5x^2 + 20x
murzikaleks [220]

Answer: 5x(x + 4)

hope i helped

7 0
2 years ago
Read 2 more answers
Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

8 0
3 years ago
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