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Stella [2.4K]
3 years ago
5

In a survey of U.S. adults with a sample size of 2062​,330said Franklin Roosevelt was the best president since World War II. Two

U.S. adults are selected at random from this sample without replacement.
​(a) Find the probability that both adults say Franklin Roosevelt was the best president since World War II.
​(b) Find the probability that neither adult says Franklin Roosevelt was the best president since World War II.
​(c) Find the probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II.
Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

a) 0.0255

b) 0.7050

c) 0.2945

Step-by-step explanation:

Probability that one of those sampled saying that Roosevelt was the best president since World War II = 330/2062 = 0.16

Probability that one of those sampled don't mention Roosevelt = (2062 - 330)/2062 = 1732/2062 = 0.84

a) The probability that both adults picked say Franklin Roosevelt was the best president since World War II = (330/2062) × (329/2061) = 0.0255

b) The probability that neither of the two adults say Franklin Roosevelt was the best president since World War II = (1732/2062) × (1731/2061) = 0.7050

c) The probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II = Probability that one of the two adults mention Roosevelt + Probability that the two adults mention Roosevelt

Probability that one of the adults mention Roosevelt = [(330/2062) × (1732/2061)] + [(1732/2062) × (330/2061)] = 0.269

Probability that two of the adults mention Roosevelt has been done in (a) and it is equal to 0.0255

probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II = 0.269 + 0.0255 = 0.2945

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KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let <em>X</em> = number of text messages receive or send in an hour.

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em>.

It is provided that users receive or send 62.7 text messages in 24 hours.

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The probability of a random variable can be computed using the formula:

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Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

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             =1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

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azamat

Answer:

180 cm2

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If so, your ''area of parallelogram'' is 15cm2 since your question is hecking  weird.

Btw it's 15cm2 not 15

Please check ur question b4 u ask

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