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Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
Add up minutes
1stmonth+2ndmonth+3rdmonth=320+243+489=1052
how many 200's are there
6 of them (companies want money so they see, ok, you bought like 1 minute, we will charge you for the whole 200 minutes since you got in that zone)
6 times 25=150
cost is $150 (mom is not going to be happy, she spend like 3% of her waking hours takling on the phone)
Answer:
I think it's A - (0,-3)
Step-by-step explanation:
x,y
(0,-3)
y-intercept equation for this problem:

Break it down to smaller parts:


Rewriting it in a neater way:
=> 
Therefore, answer A / the first choice is correct
- have a great day, be safe & healthy -