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Sonja [21]
3 years ago
5

2.

Mathematics
1 answer:
jeyben [28]3 years ago
7 0

Answer:

6 × ( 3x - 4)

Step-by-step explanation:

Not much to explain.

Hope this helps!

If there is something wrong, please let me know

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Will give brainliest! Answer honestly i will know if your writing things randomly
Alik [6]

Answer:

Mark brainliest

Step-by-step explanation:

1. E

2. C

3. F

4. B

5. D

6. A

3 0
3 years ago
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Translate the phrase into a Variable expression : The Product of y and the Sum of y and 21.
Valentin [98]
Y(y+21) If you think about it you will see that it would most likely be this answer because the product of something is multiplying, and the sum is adding. If this answer is not correct then I am sorry.
7 0
3 years ago
If f(x) = 1/3x^2 + 5, find f(-9).<br> A. 248<br> B. -22<br> C. 11<br> D. 32
melamori03 [73]

Answer:

D. 32

Step-by-step explanation:

For this problem, we simply plug -9 in for x in f(x):

f(x)=\frac{1}{3} x^2+5  ⇒  f(9)=\frac{1}{3} *(9^2)+5=\frac{1}{3} *81+5=27+5=32

Thus, the answer is D. 32.

Hope this helps!

7 0
3 years ago
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For which values of P and Q does the following equation have infinitely many solutions? Px-37=Qx-37
Lyrx [107]

Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

Step-by-step explanation:

Px - 37 = Qx - 37

Px - Qx - 37 = -37

x (P-Q) = 0

==> P-Q=0 ==> P=Q


4 0
3 years ago
GEOMETRY PROOFS!
yarga [219]

From the given figure ,

RECA is a quadrilateral

RC divides it into two parts

From the triangles , ∆REC and ∆RAC

RE = RA (Given)

angle CRE = angle CRA (Given)

RC = RC (Common side)

Therefore, ∆REC is Congruent to ∆RAC

∆REC =~ ∆RAC by SAS Property

⇛CE = CA (Congruent parts in a congruent triangles)

Hence , Proved

<em>Additional</em><em> comment</em><em>:</em><em>-</em>

SAS property:-

"The two sides and included angle of one triangle are equal to the two sides and included angle then the two triangles are Congruent and this property is called SAS Property (Side -Angle-Side)

<u>also</u><u> </u><u>read</u><u> </u><u>similar</u><u> questions</u><u>:</u> Complete this proof. Given: EC AC, DB AC, ∠A = ∠F Prove: ΔMDF ∼ ΔNCA..

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Consider the proof. Given: Segment AB is parallel to line DE. Prove: AD/DC = BE/EC What is the missing statement in Step 5? A.) AC = BC B.) AC/DC = BC/EC C.) AD...

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4 0
2 years ago
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