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sesenic [268]
3 years ago
11

Find the area of the figure

Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer: 52x+4

Step-by-step explanation: Do 16(2x-1)+4(5x+5) and get 52x+4.

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A military cannon is placed at the base of a hill. The cannon is fired at an angle toward the hill. The path
katrin [286]

Answer:

Algebracicaly speaking the answer would be either -13.3876 or - 158.612 through the quadratic equation, but these answers don’t make sense in this real world scenario.

Step-by-step explanation:

7 0
2 years ago
Pls help I don’t understand
dmitriy555 [2]

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

4 0
3 years ago
Please help !!! I’m confused
posledela

6x-21=105

+21. +21

6x=126

×=21

21y=75

Divide 21 from 75

Y= 3.6

5 0
3 years ago
Sonia uses $12.50 to buy a new journal. She has $34.25 left in her savings account. How much money did Sonia have before she bou
GalinKa [24]
So all you have to do to find out how much she had before is add up both value 12.50+34.25=   46.75$ (answer)

because y-12.50=34.25 so you would have to had the 12.5 to the other side to find the value of Y
3 0
3 years ago
Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
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