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3 years ago

Which side lengths represent the sides of a right triangle?

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Answer: the answer is C

Step-by-step explanation:

My friend is a math teacher

Hope this helps

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G(x) = f (x + 1) describe how to transform the graph

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Answer:

333

Step-by-step explanation:

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3 years ago

Jamal ran 8 kilometers, sprinted 500 meters, and climbed bleachers for a distance of 2 kilometers during track practice. How man

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10,500 I think that would be the answer

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4 years ago

What is an equivalent expression for 4y plus y

RideAnS [48]

4y plus y

= 4y + y

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3 years ago

Solve for z. 4/z =12/5

svp [43]

$\dfrac{4}{z}=\dfrac{12}{5}\\\\ 12z=20\\\\ z=\dfrac{20}{12}=\dfrac{5}{3}$

4 0

3 years ago

Read 2 more answers

What is the perimeter of rhombus WXYZ?

oksian1 [2.3K]

Answer:

The perimeter of rhombus WXYZ is $4 \sqrt{13}$

Step-by-step explanation:

Step 1 :Finding length of XY

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =3

$y_1$ = -1

$y_2$ =2

XY = $\sqrt{(3-5)^2 +(2 -(-1))^2}$

XY = $\sqrt{(3-5)^2 +(2 +1))^2}$

XY = $\sqrt{(-2)^2 +(3))^2}$

XY = $\sqrt{4 +9}$

XY = $\sqrt{(13)}$

Step 2 :Finding length of YZ

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 3

$x_2$ =5

$y_1$ = 2

$y_2$ =5

YZ = $\sqrt{(5-3)^2 +(5-2)^2}$

YZ = $\sqrt{(2)^2 +(3)^2}$

YZ = $\sqrt{4 +9}$

YZ = $\sqrt{(13)}$

Step 3 : :Finding length of ZW

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 5

$x_2$ =7

$y_1$ = 5

$y_2$ =2

ZW = $\sqrt{(7-5)^2 +(5-2)^2}$

ZW = $\sqrt{(2)^2 +(3)^2}$

ZW = $\sqrt{4 +9}$

ZW = $\sqrt{(13)}$

Step 4 :Finding length of WX

Distance formula = $\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

here

$x_1$ = 7

$x_2$ =5

$y_1$ = 2

$y_2$ = -1

WX = $\sqrt{(7-5)^2 +((-1)-2)^2}$

WX = $\sqrt{(2)^2 +(-3)^2}$

WX = $\sqrt{4 +9}$

WX = $\sqrt{(13)}$

Step 5: finding the perimeter of the rhombus

Perimeter= 4 X side

=> $4 \times \sqrt{13}$

=> $4 \sqrt{13}$

5 0

3 years ago

Read 2 more answers