The variance of the binomial distribution of the number of households with landline service is 2.
<h3>What is the binomial probability distribution?</h3>
It is the probability of <u>exactly x successes on n repeated trials, with p probability</u> of a success on each trial.
The variance of the distribution is given by:
V(X) = np(1 - p)
In this problem, the parameters are given as follows:
n = 8, p = 0.504.
Hence the variance is given by:
V(X) = 8 x 0.504 x 0.496 = 2.
More can be learned about the binomial distribution at brainly.com/question/24863377
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All of them are statistical
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
12j + 12 + 3j or 15j + 12. This is because if you use Distributive Property to distribute the 3, then you multiply 3 by all the number inside the parentheses. I have two expressions because once you get get the answer after you use the property, then you can combine like terms, such as 12j and 3j which is 15j. Hope this helps!
A) (4,6) would also be on this line. Let me know if you have any other questions!
