(From left to right):
Graph 1
Domain: All real numbers.
Range: All real numbers.
Graph 2
Domain: All real numbers.
Range: Assuming the the scaling is by one’s:
[ 3, infinity )
Graph 3
Domain: [ -2, infinity )
Range: [ -3, infinity )
Hope this helps! (:
this = 6 2/3
as an improper fraction it is 20/3
Answer:
So the inner function is g(x) = arctan(x) and the outer function is h(x) = e^(x)
Step-by-step explanation:
Suppose we have a function in the following format:
f(x) = g(h(x))
The inner function is h(x) and the outer function is g(x).
In this question:
f(x)=arctan(e^(x))
From the notation above
h(x) = e^(x)
g(x) = arctan(x)
Then
f(x) = g(h(x)) = g(e^(x)) = arctan(e^(x))
So the inner function is g(x) = arctan(x) and the outer function is h(x) = e^(x)
Answer:
(t, h(t)) = (4, 9256)
Step-by-step explanation:
We assume you intend the h(t) function to be ...
h(t) = -16t^2 +128t +9000
The equation can be written in vertex form as follows:
h(t) = -16(t^2 -8t) +9000
h(t) = -16(t^2 -8t +16) +9000 -(-16)(16) . . . . add and subtract -16(16) to complete the square
h(t) = -16(t -4)^2 +9256 . . . . . vertex form of the height function
The vertex of h(t) is (4, 9256), an altitude of 9256 feet after 4 seconds.
For this case what you must multiply the variable Z for each of the terms that are within the parenthesis and then do the corresponding subtraction.
We have then that the product will be given by:
Zx (X-4) =
(Z * X) - (Z * 4)
Rewriting:
ZX-4Z
Answer:
the product is:
ZX-4Z