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2 years ago

What is the midpoint of the segment shown below? (3,5) (2,2)

Mathematics

2 answers:

Kamila [148]2 years ago

7 0

(X, Y) = (5/2, 7/2)

Juliette [100K]2 years ago

6 0

Answer:

(5/2, 7/2)

Step-by-step explanation:

Use the midpoint formula to solve for the midpoint:

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\\\(\frac{3+2}{2},\frac{5+2}{2})\\\\(\frac{5}{2},\frac{7}{2})$

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For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les

kaheart [24]

Answer:

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation

n=1000 represent the random sample taken

$\hat p=0.52$ estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

$\alpha=0.05$ represent the significance level (no given, but is assumed)

Solution to the problem

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The margin of error for this case is given by:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

And replacing we got:

$ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259$

And replacing into the confidence interval formula we got:

$0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941$

$0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459$

And the 95% confidence interval would be given (0.4941;0.5459).

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2 years ago

Use exterior angles to show that the angle sum of quadrilateral PQRS is 360°.

Shkiper50 [21]

Answer:

I don't really know but one triangle is 180 degrees so two added together is 360 degrees...

but ohh I remembered

a=c+d (since a+b=180 and c+d+b=180)

e=g+h (since e+f=180 and g+h+f= 180)

and the fact is that c+d+g+h+b+f=the angle sum of quadrilateral PQRS

a+e+b+f= the angle sum of quadrilateral PQRS (by substitutions)

a+e+b+f=360 (four angles are from one origin so it's 360 degrees )

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3 years ago

Pls help ill give brainliest :)

Tatiana [17]

Answer:

380.

Just add the two numbers together and it'll work :)

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2 years ago